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x^2-5x+24/5=0
We multiply all the terms by the denominator
x^2*5-5x*5+24=0
Wy multiply elements
5x^2-25x+24=0
a = 5; b = -25; c = +24;
Δ = b2-4ac
Δ = -252-4·5·24
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{145}}{2*5}=\frac{25-\sqrt{145}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{145}}{2*5}=\frac{25+\sqrt{145}}{10} $
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